A

$\displaystyle\sum\limits_{n=1}^{\infty}(-1)^n\dfrac{3-4n^2}{(n+1)(n+2)}$

B

$\displaystyle\sum\limits_{n=1}^{\infty}(-1)^n\dfrac1{n+1}$

C

$\displaystyle\sum\limits_{n=1}^{\infty}(-1)^{n-1}\dfrac1{3^n}$

D

$\displaystyle\sum\limits_{n=1}^{\infty}\dfrac1{(2n+1)^{3/2}}$